8051 MICROCONTROLLER
ARCHITECTURE OF 8085
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
|
|
True
|
|
False
|
|
Either A or B
|
|
None of the above
|
Detailed explanation-1: -A computer system has an address bus with 8 parallel lines. This means that the address bus width is 8 bits. The capacity of each memory location is 16 bits (i.e. it corresponds to a word with a length of 16 bits).
Detailed explanation-2: -The Intel 8088 microprocessor is a variant of the Intel 8086. Introduced on July 1, 1979, the 8088 had an eight-bit external data bus instead of the 16-bit bus of the 8086.
Detailed explanation-3: -In 8085 microprocessor, Address bus is of 16 bits (A0-A15) and can transfer maximum 16 bit address and hence can address 65, 536 different memory locations. This bus is multiplexed with 8 bit data bus. So, the most significant bits (MSB) of address goes through Address bus and LSB goes through multiplexed data bus.