8051 SERIAL PROGRAMMING
ARCHITECTURE OF 8085
|
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
|
If two interrupts, of higher priority and lower priority occur simultaneously, then the service provided is for
|
|
interrupt of lower priority
|
|
|
interrupt of higher priority
|
|
|
lower & higher priority interrupts
|
|
|
none of the mentioned
|
Explanation:
Detailed explanation-1: -If two interrupts, occur simultaneously, then the one with higher priority level and early polling sequence will receive service. The other one with lower priority may get lost there, as there is no mechanism for storing the interrupt requests.
Detailed explanation-2: -The highest interrupt priority upon reset in 8051 is external interrupt 0.
Detailed explanation-3: -Explanation: The interrupt, RI=TI (serial port) is given the lowest priority among all the interrupts.
There is 1 question to complete.