8085 MICROPROCESSOR
ARCHITECTURE OF 8085
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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16K
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64k
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32k
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16
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Detailed explanation-1: -Using 16 bits, you can write 65536 addresses (from 0 to 65535, that’s 65536 different addresses), and address 65536 bytes. 65536 bytes is 64kB.
Detailed explanation-2: -A 16-bit integer can store 216 (or 65, 536) distinct values. In an unsigned representation, these values are the integers between 0 and 65, 535; using two’s complement, possible values range from −32, 768 to 32, 767. Hence, a processor with 16-bit memory addresses can directly access 64 KB of byte-addressable memory.
Detailed explanation-3: -It has 16 address lines, so can access 64 Kbytes of memory.
Detailed explanation-4: -The address space is 64K. 16 address lines are needed to access all of the 64K addresses.
Detailed explanation-5: -Abstract. In most computer literature the size of the processor’s memory is expressed in multiples of 210 (= 1024) which is given the abbreviation K. So, 65, 536 memory locations are written as 64K: this means the addressing range is 64K.