MICROPROCESSOR AND MICROCONTROLLER

8085 MICROPROCESSOR

FEATURE OF 8085

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
AD0-AD7 Called as
A
Address lines
B
Data lines
C
Multiplexed lines
D
All the above
Explanation: 

Detailed explanation-1: -Pins 12 to 19 of 8085 are AD0 – AD7 which is the multiplexed address-data bus. Multiplexing is done to reduce the number of pins of 8085. Lower byte of address (A0 – A7) are available from AD0 – AD7 (pins 12 to 19) during T1 of machine cycle.

Detailed explanation-2: -These eight pins are collectively called AD7-0. They are called basically “Address Data”. When the 8085 desires to send out 8-bit information, it sends it out on these same pins.

Detailed explanation-3: -Answer: Explanation: 8085 microprocessor have 16 bit address bus but its lower order bit multiplexed with 8 bit data bus (as 8085 has 8 bit data bus) to reduce number of pins so AD7-AD0 is bidirectional, whereas higher order bit only carries address so it unidirectional.

Detailed explanation-4: -AD0-AD7 carries low order byte data and AD8AD15 carries higher order byte data. During the first clock cycle, it carries 16-bit address and after that it carries 16-bit data.

Detailed explanation-5: -Why the lower byte address bus (A0 – A7) and data bus (D0 – D7) are multiplexed? Ans. This is done to reduce the number of pins of 8085, which otherwise would have been a 48 pin chip. But because of multiplexing, external hardware is required to demultiplex the lower byte address cum data bus.

There is 1 question to complete.