8085 MICROPROCESSOR
FEATURE OF 8085
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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4
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5
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6
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8
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Detailed explanation-1: -There are 8 software interrupts in 8085, i.e. RST0, RST1, RST2, RST3, RST4, RST5, RST6, and RST7. Hardware interrupt − There are 5 interrupt pins in 8085 used as hardware interrupts, i.e. TRAP, RST7.5, RST6.5, RST5.5, INTA.
Detailed explanation-2: -In the 8085 microprocessor, Five interrupts are maskable. There are five hardware interrupts.
Detailed explanation-3: -The hardware interrupts are initiated by an external device by placing an appropriate signal at the interrupt pin of the processor. If the interrupt is accepted, then the processor executes an interrupt service routine (ISR). Hence there are total 13 interrupts in 8085.
Detailed explanation-4: -The “5” in the part number highlighted the fact that the 8085 uses a single +5-volt (V) power supply by using depletion-mode transistors, rather than requiring the +5 V, −5 V and +12 V supplies needed by the 8080. This capability matched that of the competing Z80, a popular 8080-derived CPU introduced the year before.
Detailed explanation-5: -It is a 1-Byte instruction. It is functionally same as CALL 0020H = PUSH PC + JMP 0010H. It causes a branch to subroutine starting from memory address 0020H. Similarly, RST 5 causes a branch to a subroutine at 5*8 = 0028H.