INTRODUCTION TO MICROPEOCESSOR
MICROCOMPUTER SYSTEM
|
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
|
This is the formula for the maximum cconversion time that will occur when VA is just below full scale
|
|
tc(max) = (2N-1) x clock period
|
|
|
tc(min) = (2N-1) x clock period
|
|
|
tc(max) = (2N+1) x clock period
|
|
|
tc(min) = (2N+1) x clock period
|
Explanation:
Detailed explanation-1: -For example, if the converter’s DAC had a 200-nsec settling time and we used a 5-MHz clock for a 12-bit ADC, maximum conversion time would be 1 5 × 10 6 × 4096 = 819.2 sec This would allow a conversion rate of only 1220 samples per second.
Detailed explanation-2: -Maximum conversion time is equal to (2n-1 )* TCLK for n-bit of ADC. The conversion time depends on analog input voltage.
Detailed explanation-3: -The conversion rate is entered in samples per second. The maximum conversion rate depends on the resolution. To convert one sample, it takes 18 cycles at 12 bit resolution, 16 cycles at 10 bits, and 14 cycles at 8 bits. So, the conversion rate of SAR will be clock frequency / (resolution + 6 cycles).
There is 1 question to complete.