MICROPROCESSOR AND MICROCONTROLLER

PIC MICROCONTROLLER

ARCHITECTURE OF 8085

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
Calculate Instruction Cycle (I.C.) if FOSC = 12MHz
A
333.333 ns
B
0.333 s
C
0.333 ks
D
3.333 us
Explanation: 

Detailed explanation-1: -Detailed Solution The crystal frequency of 8051 is 12 MHz . Therefore the machine cycle for a system of 12MHz is µ 1 µ s .

Detailed explanation-2: -Calculation of IPC The number of instructions per second and floating point operations per second for a processor can be derived by multiplying the number of instructions per cycle with the clock rate (cycles per second given in Hertz) of the processor in question.

Detailed explanation-3: -In 8051-based system, the crystal oscillator has a frequency of 11.0592 MHz when C/T bit of TMOD is 0. Each machine cycle is made up of 12 clock cycles. Hence for a single machine cycle, the frequency becomes 1/12 × 11.0529 MHz = 921.6 KHz.

Detailed explanation-4: -With a 12 MHz clock frequency, the 8051 could thus execute 1 million one-cycle instructions per second or 500, 000 two-cycle instructions per second.

There is 1 question to complete.