NURSING EXAM QUESTIONS
BIOCHEMISTRY
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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Glucose-6-Phosphate
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Fructose-6-Phosphate
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ATP
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1, 6 Bis-PhosphoGlycerate
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Detailed explanation-1: -During glycolysis, glucose ultimately breaks down into pyruvate and energy; a total of 2 ATP is derived in the process (Glucose + 2 NAD+ + 2 ADP + 2 Pi–> 2 Pyruvate + 2 NADH + 2 H+ + 2 ATP + 2 H2O). The hydroxyl groups allow for phosphorylation. The specific form of glucose used in glycolysis is glucose 6-phosphate.
Detailed explanation-2: -Glucose-6 phosphate is the first intermediate of glucose metabolism and plays a central role in the energy metabolism of the liver. It acts as a hub to metabolically connect glycolysis, the pentose phosphate pathway, glycogen synthesis, de novo lipogenesis, and the hexosamine pathway.
Detailed explanation-3: -Step 1. In the first step of glycolysis, a phosphate group is transferred from ATP to glucose, creating glucose-6-phosphate. This reaction is called phosphorylation and is catalyzed by the enzyme hexokinase.
Detailed explanation-4: -Stage 2: Isomerization of Glucose-6-Phosphate Glucose-6-phosphate (G6P) is changed into fructose-6-phosphate (F6P) by phosphoglucoisomerase (phosphoglucose isomerase) in the second step. This reaction also requires Mg2+. F6P can enter the glycolytic pathway from the next point.