NURSING ANM AND GNM

NURSING EXAM QUESTIONS

MICROBIOLOGY

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
The formation of citrate from oxaloacetate and an acetyl-CoA begins
A
the Kreb’s cycle
B
glycolysis
C
the electron transport chain
D
oxidative phosphorylation
Explanation: 

Detailed explanation-1: -The Acetyl CoA produced enters the Tricarboxylic acid cycle or Citric acid cycle. Glucose is fully oxidized in this process. The acetyl CoA combines with 4-carbon compound oxaloacetate to form 6C citrate. In this process, 2 molecules of CO2 are released and oxaloacetate is recycled.

Detailed explanation-2: -The Krebs cycle itself actually begins when acetyl-CoA combines with a four-carbon molecule called OAA (oxaloacetate) (see Figure above). This produces citric acid, which has six carbonatoms. This is why the Krebs cycle is also called the citric acid cycle.

Detailed explanation-3: -The first step of the citric acid cycle is the formation of citrate from oxaloacetate and acetyl-CoA. This step is a two-step process that is catalyzed by an enzyme called citrate synthase. The first step of this process is an aldol condensation that produces an intermediate molecule called citryl-CoA.

Detailed explanation-4: -The first step is fusion of the acetyl group of acetyl-CoA with oxaloacetate, catalyzed by citrate synthase. CoA-SH and heat are released and citrate is produced. Citrate is isomerized by dehydration and rehydration to isocitrate.

There is 1 question to complete.