PATHOLOGY MCQ
GENETICS AND DISEASE
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
|
|
XHXH and XHY
|
|
XHXH and XhY
|
|
XHXh and XHY
|
|
XHXh and XhY
|
Detailed explanation-1: -If a mother is heterozygous (a carrier) for hemophilia and the father does not have hemophilia, each son has a 1 in 2 (50%) chance of getting his mother’s hemophilia allele and having hemophilia. Each daughter has a 1 in 2 (50%) chance of getting her mother’s hemophilia allele and being heterozygous.
Detailed explanation-2: -Since this is a recessive disorder, one XH allele will give a normal phenotype. When the offspring do not have a XH and only have the Xh allele/alleles they will have the hemophilia condition. Man’s genotype is XhY. Daughter’s genotype is XHXh (She got the Xh from her father.
Detailed explanation-3: -A man who has hemophilia and a woman who is a carrier have: a 25% (one in four) chance of having a son with hemophilia. a 25% chance of having a son with normal blood clotting. a 25% chance of having a daughter who is a carrier.
Detailed explanation-4: -There is a 50% chance that a female carrier’s son (XY) will have hemophilia and a 50% that her daughter (XX) will be a carrier just like her.