USA HISTORY

SECTIONAL CRISIS 1850 1861

JOHN BROWNS RAID

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
How many men did John Brown lead into Harpers Ferry
A
is “army” grew to include 22 men, including five black men and three of Brown’s sons.
B
is “army” grew to include 1550 men, including five black men and three of Brown’s sons.
C
is “army” grew to include 2 men, including five black men and three of Brown’s sons.
D
is “army” grew to include 23 men, including five black men and three of Brown’s sons.
Explanation: 

Detailed explanation-1: -Harper’s Ferry before John Brown’s raid on October 16, 1859. On October 16, 1859, John Brown led a small army of 18 men into the small town of Harper’s Ferry, Virginia. His plan was to instigate a major slave rebellion in the South.

Detailed explanation-2: -On October 16, Brown set out for Harpers Ferry with 21 men–5 blacks, including Dangerfield Newby, who hoped to rescue his wife who was still a slave, and 16 whites, two of whom were Brown’s sons. Leaving after sundown, the men crossed the Potomac, then walked all night in heavy rain, reaching the town at 4am.

Detailed explanation-3: -On July 3, 1859, Brown arrived in Harpers Ferry, accompanied by his sons, Oliver and Owen, and Jeremiah Anderson. In the preceding months, he had raised money from other abolitionists and ordered weapons-pikes and guns-to be used in his war against slavery.

Detailed explanation-4: -Sixteen people were killed in the raid, including ten of Brown’s men. John Brown, Aaron Stevens, Edwin Coppoc, Shields Green, and John Copeland were taken to jail in Charles Town, Virginia, on October 19. Albert Hazlett and John Cook were subsequently captured and jailed with the others.

Detailed explanation-5: -About 50 black and white supporters adopted Brown’s anti-slavery constitution. In December, Brown moved beyond talk and plans. He led a daring raid from Kansas across the border into Missouri, where he killed one slave owner and freed 11 slaves.

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