GK
CHEMISTRY
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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A 22.4-L sample of which of the following substances, at STP, would contain 6.02 X 1023 representative particles?
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oxygen
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gold
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cesium iodide
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sulfur
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Explanation:
Detailed explanation-1: -Answer and Explanation: Therefore, the correct choice is oxygen.
Detailed explanation-2: -Oxygen gas is made up of diatomic molecules (O2). Therefore 22.4 L of oxygen gas at STP contains 1 mole of O2 molecules.
Detailed explanation-3: -Hence we get the ans as 6.022*10^20 molecules.
Detailed explanation-4: -Key Point: We know at STP, one mole of a gas occupies 22.4 L ( you can find this by solving PV = nRT. But it is better to remember it. so 22.4 L of CO gas is one mole of CO gas. therefore 22.4 L of CO gas contains 6.02 x 10^23 number of atoms.
There is 1 question to complete.