GENERAL KNOWLEDGE

GK

CHEMISTRY

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
An atom of iodine has 7 valence electrons. What will an atom of iodine MOST likely do to be stable?
A
Lose 1 electron
B
Lost 7 electrons
C
Gain 1 electron
D
Neither gain nor lose any valence electrons
Explanation: 

Detailed explanation-1: -On the other hand, iodine is located in group 17 (main group 7), which means it has 7 valence electrons. It is easier for iodine to gain an electron rather than to lose 7, so it will form an anion, or negatively charged ion, I− .

Detailed explanation-2: -Valence Electrons are the electrons located on the highest energy level of the atom. In the case of Iodine, the highest energy level is n=5. So, after adding the electrons present in subshell 5s, 5p total number of valence electrons come out to be seven.

Detailed explanation-3: -Answer and Explanation: The atom that is most likely to form a-1 ion is potassium. This is because it will attain a stable electronic configuration with-1 charge.

Detailed explanation-4: -Answer and Explanation: The answer is (b)-1. The Iodine atom has 7 valence electrons present in the outer shell. In order to achieve the octet of valence electrons (8 valence electrons), it needs to accept or gain an extra electron.

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