GK
CHEMISTRY
|
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
|
How many grams are there in 7.40 moles of AgNO3?
|
|
0.043 grams
|
|
|
680 grams
|
|
|
0.140 grams
|
|
|
1260 grams
|
Explanation:
Detailed explanation-1: -Therefore, number of grams of AgNO3 present in its 7.4 moles is 1257.
Detailed explanation-2: -The molecular weight of silver nitrate= sum of the atomic mass of atoms in one molecule of AgNO3. O (3) = 3X16. 0=48.0 grams. Hence the molar mass of the Silver Nitrate (AgNO3) is 107 + 14 + 48 = 169.9 g/mol.
Detailed explanation-3: -The number of moles of AgNO3 in 22.6g can be determined by using the molar mass of the substance. The molar mass of AgNO3 is 169.87 g/mol. Dividing the mass of AgNO3 (22.6g) by the molar mass (169.87 g/mol) gives 0.25 moles of AgNO3 in 22.6g.
Detailed explanation-4: -Hence, the number of moles present in 24 g of carbon is 2.
There is 1 question to complete.