GENERAL KNOWLEDGE

Detailed explanation-1: -silver iodide behaves as a sparingly soluble salt in solutions of sodium iodide in water, methyl alcohol, and ethyl alcohol. Some results are now given which show that, whereas silver iodide is practically insoluble in pure acetone, it is easily soluble in solutions of alkali iodide in acetone-more than 3 g.

Detailed explanation-2: -Silver iodide is a compound which is inorganic in nature and Sodium iodide is a soluble compound in water and it is an ionic compound. Complete step-by-step answer:The solubility of $AgI$ in $NaI$ solution is less than that in pure water because solubility is reduced because of common ion effect.

Detailed explanation-3: -AgI seems to be the least soluble mainly because it has the most covalent character, and the two atoms have the most similar atomic radii in context, thereby forming the strongest bond in the lattice structure.

Detailed explanation-4: -AgI is practically insoluble in water. Only 3 x 10-7 g will dissolve in 100mL of water at 20 °C.

Detailed explanation-5: -Lead(II) iodide is insoluble in water.