GK
CHEMISTRY
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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1s22s22p63s2, 3p64s23d104p5
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1s22s22p4
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1s22s22p6
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1s22s22p63s23p64s23d1
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Detailed explanation-1: -In writing the electron configuration for oxygen the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for O go in the 2s orbital. The remaining four electrons will go in the 2p orbital. Therefore the O electron configuration will be 1s22s22p4.
Detailed explanation-2: -Expert Answer The atomic number of oxygen(O) is 8, and its atom contains 8 electrons. The electron configuration of atomic oxygen is 1s2 2s2 2p4.
Detailed explanation-3: -In a neutral oxygen atom, there are also 8 electrons. The electron configuration 1s22s22p4 has a total of 8 electrons.
Detailed explanation-4: -The electronic configuration of Oxygen is 1 s 2 2 s 2 2 p 4 . Oxygen requires two electrons to attain noble gas configuration.
Detailed explanation-5: -An oxygen atom, having electron configuration 1s2 2s2 2p4, forms a single bond with another oxygen atom. In an ionic bond, two cations can bond together to form a compound. The name of an oxyacid has the suffix-ic acid.