GK
CHEMISTRY
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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What is the percent composition of a compound that contains 40.8 g carbon and 54.4 g oxygen?
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42.9 % carbon; 57.1% oxygen
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57.1 % carbon; 42.9 % oxygen
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40.8 % carbon; 54.4 % oxygen
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54.4 % carbon; 40.8% oxygen
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Explanation:
Detailed explanation-1: -%C=40.8⋅g95.2⋅g×100%=42.9% . %O=54.4⋅g95.2⋅g×100%=57.1% .
Detailed explanation-2: -The empirical formula is CH2O .
Detailed explanation-3: -Then we have 40.00 g of C, 6.72 g of H, and 53.28 g of O. The empirical formula is CH₂O.
Detailed explanation-4: -Therefore, the molecular formula of the given compound is C2H4O2.
Detailed explanation-5: -Now, to know the percent composition of Carbon and Oxygen . We will divide their weight with the total weight of CO2. % C = 12.01/44.01 = 0.2729= 27.29% (we will divide 0.2729 with 100 to take the percentage). % O = 32.00/44.01 =0.7271 =72.71 %O in CO2.
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