GK
NUCLEAR SCIENCE
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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Mass excess for U-235 is
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0.05 u
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0.06 u
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0.034 u
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0.043 u
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Explanation:
Detailed explanation-1: -The mass excess can be converted into energy using 1 Da = 931.494 MeV/c2, and E = mc2, yielding 166.737 MeV.
Detailed explanation-2: -Mass defect in nuclear reaction is =0.2a.m.u. The mass defect is converted into energy released. Therefore, the total energy released during the fission of one uranium-235 nucleus is 186.2 MeV.
Detailed explanation-3: -Add the masses of the initial neutron and the U-235 in atomic mass units: m(n) = 1.008665 amu and m(U-235) = 235.04395 amu; m(n) + m(U-235) = 236.052615 amu.
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