GK
NUCLEAR SCIENCE
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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10 MeV
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100 MeV
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1000 MeV
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10000 MeV
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Detailed explanation-1: -The energy released in U-235 fission is about 0.8 MeV per nucleon . Thus energy released per atom is about 0.8×235≃200MeV.
Detailed explanation-2: -Energy released in the fission of a single 92U235 nucleus is 200 MeV. The fission rate of a 92U235 fuel reactor operating at a power level of 5 W is 1.56×105.5k s−1.
Detailed explanation-3: -The mass of 23592U which must go nuclear fission to produce the same mass of energy as produced by 1 ton of coal. Given the heat of combustion of coal is 8×103cal/g. The fission of 23592U produces 200 MeV energy per fission.
Detailed explanation-4: -One fission event results in the release of about 200 MeV of energy, or about 3.2 ´ 10-11 watt-seconds. Thus, 3.1 ´ 1010 fissions per second produce 1 W of thermal power.