GK
PHYSICS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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A 500-g bottled water fell from a 20-m tall building. Just before hitting the ground, what will be its kinetic energy if air resistance is negligible?
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98 J
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0 J
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98, 000
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10 J
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Explanation:
Detailed explanation-1: -F=mav−u=20sw=f. x=5000×20w=100kg.
Detailed explanation-2: -A 500 g ball is released from a height of 4 m. Each time it makes contact with the ground it loses 25% its energy.
Detailed explanation-3: -Let’s assume the height of the object from ground is hm, the object is initially at rest so the initial velocity of the object is Vi=0m/s V i = 0 m / m s s, and the final velocity before hits the ground is Vf=Vm/s V f = V m / m s s .
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