GENERAL KNOWLEDGE

GK

PHYSICS

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
A 931-g object is attached to a spring with spring constant of 587 N/m and is undergoing simple harmonic motion. What is the object’s horizontal displacement if the spring force is 50 N?
A
-0.09 m
B
0.09 m
C
-0.9 m
D
0.9 m
Explanation: 

Detailed explanation-1: -The displacement of an object attached to a spring and executing simple harmonic motion is given by x=2×10−2cost metres.

Detailed explanation-2: -Displacement (x): Displacement of a body executing Simple Harmonic Motion is defined as the net distance traveled by the body from its mean or equilibrium position.

Detailed explanation-3: -A body of mass m is attached to a spring of spring constant k which hangs from the ceiling of an elevator at rest in equilibrium. Now the elevator starts accelerating upwards with its acceleration varying as a=pt+q, where p and q are positive constants.

Detailed explanation-4: -A Hooke’s Law Spring. Hooke’s Law states that the restoring force of a. where x is the size of the displacement. 50 grams mass is 2 cm displacement. 150 grams mass is 6 cm displacement. W is the weight of the added mass. As stated above the relationship depicted on the graph is W = kx where k is the spring constant.

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