GK
PHYSICS
|
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
|
A merry-go-round, initially at rest, rotates with a constant acceleration of 0.05 rad/s2 . What is the time interval required for it to reach a 23-rad displacement?
|
|
30 s
|
|
|
35 s
|
|
|
40 s
|
|
|
45 s
|
Explanation:
Detailed explanation-1: -A merry-go-round rotates from rest with constant angular acceleration ‘a’.
Detailed explanation-2: -A merry-go-round rotates from rest with an angular acceleration of 1.50 rad/s2 .
Detailed explanation-3: -Angular Acceleration Unit In SI units, angular acceleration is measured in radians per second squared (rad/s2) and is usually denoted by the alpha ().
Detailed explanation-4: -Expert-Verified Answer Given that merry go round starts from rest. So 0 = 0 rad/s. Therefore, ratio of time to rotate first 2 revolutions & next 2 revolutions is √2+1.
There is 1 question to complete.