GK
PHYSICS
|
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
|
A merry-go-round, rotating initially at an angular speed of 0.23 rad/s, accelerates over a 3-s interval at a rate of 0.09 rad/s2 . What is its angular speed after this 3-s interval?
|
|
0.5 rad/s
|
|
|
0.9 rad/s
|
|
|
1.5 rad/s
|
|
|
1.9 rad/s
|
Explanation:
Detailed explanation-1: -A merry-go-round rotates from rest with an angular acceleration of 1.50 rad/s2 .
Detailed explanation-2: -Using the same expression above, this would give the merry go round an angular speed of 1.7 rad/s.
Detailed explanation-3: -The direction of the angular acceleration vector is perpendicular to the plane in which the rotation takes place. If the increase in angular velocity appears clockwise with respect to an observer, then the angular acceleration vector points away from the observer.
There is 1 question to complete.