GK
PHYSICS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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A point charge Q is far from all other charges. At a distance of 2 m from Q, the electric field is 20 N/C. What is the force a charge of 5 Coulombs feels?
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4 N
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100 N
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40 N
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10 N
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Explanation:
Detailed explanation-1: -Expert-Verified Answer We have to find the electric field at point P(2, 1, 2) due to a point charge 5C placed at origin. Therefore the electric field intensity at point P is (10/3 i + 5/3 j + 10/3 k) × 10³ N/C.
Detailed explanation-2: -The magnitude of an electric field is directly proportional to the density of electric field lines. When the lines are closer to each other, the electric field is the strongest, when the field lines are far apart from each other, the electric field is the weakest. More items
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