GENERAL KNOWLEDGE

GK

PHYSICS

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
A spring of spring constant 30.0 N/m is attached to a mass of 1.9 kg; find the period and frequency of vibration for this system.
A
1.6 s; 0.62 Hz
B
0.25 s; 0.0014 Hz
C
0.43 s; 0.0072 Hz
D
None of the above
Explanation: 

Detailed explanation-1: -Regarding the calculation formula of natural frequency (f), the general formula f=1/(2)×√(k/m) calculates the frequency f of the vibration system consisting of an object with mass m and a spring with spring constant k.

Detailed explanation-2: -The frequency f of vibrations of a mass m suspended from a spring of spring constant k is given by f=Cmxky, where C is a dimensionless constant.

Detailed explanation-3: -Mass on a spring-Where a mass m attached to a spring with spring constant k, will oscillate with a period (T). Described by: T = 2√(m/k).

Detailed explanation-4: -It’s equal to the spring constant times , the displacement of the spring from its natural length. And just like we said, this mass is stationary as it hangs off the end of the spring. That means these two forces are equal in magnitude to one another. In other words, we can write that times is equal to times .

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