GK
PHYSICS
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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0.56 N/ cm
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0.77 N/ cm
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1.3 N/ cm
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1.8 N/ cm
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Detailed explanation-1: -A spring, which obeys Hooke’s law, has an unstretched length of 10 cm. A load of 20 N is suspended from the spring. The new length of the spring is 36 cm.
Detailed explanation-2: -F =-kx. The proportional constant k is called the spring constant. It is a measure of the spring’s stiffness. When a spring is stretched or compressed, so that its length changes by an amount x from its equilibrium length, then it exerts a force F =-kx in a direction towards its equilibrium position.
Detailed explanation-3: -Mathematically, Hooke’s law states that the applied force F equals a constant k times the displacement or change in length x, or F = kx.
Detailed explanation-4: -W = kx. W is the weight of the added mass. Therefore, the spring constant k is the slope of the straight line W versus x plot. Weight is mass times the acceleration of gravity or W = mg where g is about 980 cm/sec2.
Detailed explanation-5: -It’s used to determine stability or instability in a spring, and therefore the system it’s intended for. As a formula, it reworks Hooke’s Law and is expressed through the equation: k = – F/x. Where k is the spring constant, F is the force applied over x, and x is the displacement by the spring expressed in N/m.