GK
PHYSICS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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1 m/s
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9.8 m/s
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0
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19.6 m/s
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Detailed explanation-1: -Near Earth’s surface, the gravity acceleration is approximately 9.81 m/s2 (32.2 ft/s2), which means that, ignoring the effects of air resistance, the speed of an object falling freely will increase by about 9.81 metres (32.2 ft) per second every second.
Detailed explanation-2: -Gravity will accelerate any object at a rate of 32 feet per second per second. But what do we do with that number? What it means is that if we fall for one second we’ll reach a speed of 32 feet per second.
Detailed explanation-3: -In fact, its velocity increases by 9.8 m/s2, so by 1 second after an object starts falling, its velocity is 9.8 m/s. By 2 seconds after it starts falling, its velocity is 19.6 m/s (9.8 m/s + 9.8 m/s), and so on.
Detailed explanation-4: -The magnitude of the acceleration due to gravity, denoted with a lower case g, is 9.8 m/s2. g = 9.8 m/s2. This means that every second an object is in free fall, gravity will cause the velocity of the object to increase 9.8 m/s. So, after one second, the object is traveling at 9.8 m/s.