GENERAL KNOWLEDGE

GK

PHYSICS

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
An airplane accelerates down a runway at 3.20 m/s/sfor 8 s until it finally lifts off the ground.Determine the velocity at take-off.
A
0.4 m/s
B
25.6 m/s
C
2.5 m/s
D
None of the above
Explanation: 

Detailed explanation-1: -The distance covered by the aeroplane before takeoff is 1721.3m .

Detailed explanation-2: -We can find the distance traveled before takeoff from the kinematic equation: d=v 0 t+1/2 at^2, here, d is the distance traveled before takeoff, v 0=0 is the initial velocity of the airplane, a is the acceleration of the airplane and t is the time.

Detailed explanation-3: -The vertical acceleration is given by the following equation: ( av(t) = ( [T(t)-D(t)] * sin b-W ) / m ). The horizontal acceleration is give by: ( ah(t) = ( [T(t)-D(t)] * cos b ) / m ). If the flight path was perfectly vertical, the inclination angle would be 90 degrees.

Detailed explanation-4: -The distance traveled by an object given its initial velocity and acceleration over a period of time is given by the equation d=V vt+1/2at2 .

There is 1 question to complete.