An object of mass 0.80 kg is moving in a straight line at a velocity of 2.0 m / s. A force is exerted on the object, in the direction of motion, for a period of 1.0 minute and the velocity of the object increases to 6.0 m / s. What force is exerted on the object?

PHYSICS

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Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]

A	0.053 N
B	0.080 N
C	3.2 N
D	4.8 N

Explanation:

Detailed explanation-1: -A block having mass of 0.80 kg is given an initial velocity v 1.2 m/s to the right and collides with a spring whose mass is negligible and whose force constant is k = 50 Nlm. Assuming the surface to be frictionless, calculate the maximum compression of the spring after the collision: 0.08 m 0.10 m 0.19 m 0.15 m.

Detailed explanation-2: -The correct answer is mv. Momentum: The momentum, p of an object is defined as the product of its mass, m and velocity, V. Momentum = Mass x Velocity.

Detailed explanation-3: -US) b) An object of mass 16 kg is moving with an acceleration of 3 m/s2 Calculate the applied force. If the same force is applied on an object of mass 24 kg, how much will be the acceleration? (Ans: 48 N, 2 m/s2) Was this answer helpful?

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GENERAL KNOWLEDGE

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PHYSICS