GK
PHYSICS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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Calculate kinetic energy of 0.25mol of He at 127degress celcius (R= 8.31)
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1247j
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1190j
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1210j
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6427j
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Explanation:
Detailed explanation-1: -Expert-Verified Answer. The require answer is 4.99kJ.
Detailed explanation-2: -Where n is the number of moles of argon, R is the gas constant and T is the temperature in kelvin. Therefore the kinetic energy of 10 grams of Argon molecules at 127℃ is 1248J.
Detailed explanation-3: -Kinetic energy possessed by 1g of helium gas at NTP is 850.7J.
Detailed explanation-4: -Formula. K = (3/2) * (R / N) * T. Temperature (Kelvin) Gas Constant. Avogadro’s Number. 05-Oct-2022
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