GENERAL KNOWLEDGE

GK

PHYSICS

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
For a system in simple harmonic motion, which of the following is the number of cycles or vibrations per unit of time?
A
amplitude
B
period
C
frequency
D
revolution
Explanation: 

Detailed explanation-1: -Therefore, the period T it takes for the mass to move from A to −A and back again is T = 2, or T = 2/. The frequency of the vibration in cycles per second is 1/T or /2.

Detailed explanation-2: -frequency, in physics, the number of waves that pass a fixed point in unit time; also, the number of cycles or vibrations undergone during one unit of time by a body in periodic motion.

Detailed explanation-3: -The frequency is the number of cycles per unit time, such as cycles per second, or hertz. The lowest point in the swing of a pendulum is called the equilibrium position, and the maximum displacement from equilibrium is called the amplitude.

Detailed explanation-4: -A sequence of events that repeats itself is called a cycle. The sine function repeats itself after it has “moved” through 2 radians of mathematical abstractness. The motion of a simple harmonic oscillator repeats itself after it has moved through one complete cycle of simple harmonic motion.

Detailed explanation-5: -Simple harmonic motion is repetitive. The period T is the time it takes the object to complete one oscillation and return to the starting position. The angular frequency is given by = 2/T. The angular frequency is measured in radians per second.

There is 1 question to complete.