GK
PHYSICS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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10 m/s^2
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8.9 m/s^2
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9.8 m/s^2
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0 m/s^2
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Detailed explanation-1: -The acceleration of gravity (also referred to as the gravitational field strength) at the surface of the earth has an average of 9.807ms2, which means that an object dropped near earth’s surface will accelerate downward at that rate.
Detailed explanation-2: -g = 9.8 m/s2 This means that every second an object is in free fall, gravity will cause the velocity of the object to increase 9.8 m/s. So, after one second, the object is traveling at 9.8 m/s.
Detailed explanation-3: -The acceleration due to gravity near the earth’s surface is 9.8 m/s2, and the earth’s radius is 6400 km.
Detailed explanation-4: -Acceleration due to gravity is represented by g. The standard value of g on the surface of the earth at sea level is 9.8 m/s2.