GK
PHYSICS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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1 V
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2 V
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3 V
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4 V
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Detailed explanation-1: -If a parallel plate capacitor of plate area 2m2 and plate separation 1m store the charge of 1.77*10-11 C. What is the voltage across the capacitor? On substituting values of d, A, we get C=2€0. V=1 V.
Detailed explanation-2: -Final Answer: 1130 km2. Q. What is the area of the plates of a 2 F parallel plate capacitor, given that the separation between the plates is 0.5 cm? [You will realisefrom your answer why ordinary capacitors are in the range of F orless.
Detailed explanation-3: -The area of a parallel plate capacitor is 1 ‘m^2‘ and the separation between its two plates is ‘10^(-4)m‘ . The intermediate space is filled with a material of dielectric constant 7. A certain amount of charge raises its potential to 300 V.
Detailed explanation-4: -For parallel plate capacitors, the capacitance (dependent on its geometry) is given by the formula C=⋅Ad C = ⋅ A d, where C is the value of the capacitance, A is the area of each plate, d is the distance between the plates, and is the permittivity of the material between the plates of the parallel capacitor.
Detailed explanation-5: -so area of plate, A=Cd=8. 85×103×(5×10)=1. 694×109m2.