GK
PHYSICS
|
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
|
|
|
equal to the true weight
|
|
|
less than the true weight
|
|
|
more than the true weight
|
|
|
may be more or less than true weight
|
Detailed explanation-1: -Apparent weight of the body in a lift accelerating upward with acceleration a is m (g + a) therefore the weight feels more than what it is in side a lift accelerating upwards.
Detailed explanation-2: -Detailed Solution So, when a lift accelerates upwards, the apparent weight of the person inside it increases. So, when a lift accelerates downwards, the apparent weight of the person inside it decreases.
Detailed explanation-3: -Assertion :The apparent weight of a body of mass m in an elevator moving with a downward acceleration ‘a’ is R=m(g−a) Reason: The part of weight (mg) spent on producing downward acceleration ‘a’ is ma. Therefore apparent weight =mg−ms=m(g−a).
Detailed explanation-4: -Detailed Solution Thus, the apparent weight of a man in moving lift with acceleration is less than his real weight when it is going down with an acceleration.
Detailed explanation-5: -When a lift is going up with uniform acceleration, the apparent weight of a person is W1. When the lift is stationary, his apparent weight is W2. When the lift falls freely his apparent weight is W3.