GK
PHYSICS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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Radium-226 undergoes alpha decay to become radon-222. The equation is:226 Ra 222 Rn + 4 He. 88 86 2Calculate the energy released if Ra-226 = 226.025406 u Rn-222 = 222.017574 u He = 4.002603 u
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7.81 x 10-11 J
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7.81 x 10-12 J
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7.81 x 10-13 J
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7.81 x 10-14 J
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Explanation:
Detailed explanation-1: -Answer and Explanation: Radon is produced when radium-226 undergoes alpha decay.
Detailed explanation-2: -Initially, the nucleus of Radium−226 is at rest. It decays by emitting an − particle, and thus the nucleus of Radon is created. The released energy during the decay is 4.87 MeV, which appears as the kinetic energy of the two resulted particles.
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