GK
PHYSICS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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The distance in meters traveled by a particle is related to time (t) in seconds by the equation of motion-S = 10 t +4 t2. What is the initial velocity of the body?
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4 m/s
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6 m/s
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10 m/s
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10 m/s2
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Explanation:
Detailed explanation-1: -Answer and Explanation: The velocity of the particle is v(t)=−(t−3)2+4 v ( t ) = − ( t − 3 ) 2 + 4 . Hence, the total distance traveled by the particle from t=0 to t=4 is 343 mm 34 3 m m .
Detailed explanation-2: -The distance travelled by a particle in time t is given by ‘s=(2.5m/s^2)t^2‘.
Detailed explanation-3: -To find the initial velocity: Work out which of the displacement ( s ), final velocity ( v ), acceleration ( a ), and time ( t ) you have to solve for initial velocity (u). If you have v, a, and t, use: u = v − at .
Detailed explanation-4: -Answer: The velocity after 10 seconds will remain the same i.e. 10 m/s. Hence, the velocity after 10 seconds will remain the same i.e. 10 m/s.
There is 1 question to complete.