GK
PHYSICS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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The maximum height of a projectile is
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U²sin²∅/2g
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U²cos²∅/2g
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U²tan²∅/2g
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U²sin∅/2g²
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Explanation:
Detailed explanation-1: -Thus, the maximum height of the projectile formula is, H = u 2 sin 2 2 g .
Detailed explanation-2: -The range of a projectile is the horizontal distance it travels from its launch point to the impact point. The range is calculated using the following formula: R=u2sin2g.
Detailed explanation-3: -Hence the angle of projection should be 36.86 degrees.
Detailed explanation-4: -Maximum height formula The formula to calculate the maximum height of a projectile is: ymax = y0 + V0y²/(2g); or. ymax = y0 + V02sin2/(2g)
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