GK
PHYSICS
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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-9.81 m/s/s
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-25 m/s/s
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3 m/s/s
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None of the above
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Detailed explanation-1: -Near the surface of the Earth, an object in free fall in a vacuum will accelerate at approximately 9.8 m/s2, independent of its mass. With air resistance acting on an object that has been dropped, the object will eventually reach a terminal velocity, which is around 53 m/s (190 km/h or 118 mph) for a human skydiver.
Detailed explanation-2: -"9.81 meters per second squared” means that objects on Earth will accelerate (or go faster) 9.81 meters every second, if they are in free fall, due to the pull of gravity. Throughout space, gravity actually is constant.
Detailed explanation-3: -A matter of fact, this quantity known as the acceleration of gravity is such an important quantity that physicists have a special symbol to denote it-the symbol g. The numerical value for the acceleration of gravity is most accurately known as 9.8 m/s/s.
Detailed explanation-4: -When gravity pulls objects toward the ground, it always causes them to accelerate at a rate of 9.8 m/s2. Regardless of differences in mass, all objects accelerate at the same rate due to gravity unless air resistance affects one more than another.
Detailed explanation-5: -Near Earth’s surface, the gravity acceleration is approximately 9.81 m/s2 (32.2 ft/s2), which means that, ignoring the effects of air resistance, the speed of an object falling freely will increase by about 9.81 metres (32.2 ft) per second every second.