GK
PHYSICS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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T=2×l/g²
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T=2×lg
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T=2×√l/g
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T=2×√l/g²
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Detailed explanation-1: -The time period of a simple pendulum is given by T=2√lg. The measured value of the length of pendulum is 10 cm known to 1 mm accuracy. The time for 200 oscillations of the pendulum is found to be 100 second using a clock of 1 s resolution. The percentage accuarcy in the determination of g using this pendulum is x.
Detailed explanation-2: -The period of oscillation of a simple pendulum of length l is given by T=2√l/g. The length l is about 10 cm and is known to 1 mm accuracy. The period of oscillation is about 0.5 s. The time of 100 oscillations has been measured with a stop watch of 1 s resolution.
Detailed explanation-3: -The formula for the period T of a pendulum is T = 2 Square root of√L/g, where L is the length of the pendulum and g is the acceleration due to gravity.
Detailed explanation-4: -The period of oscillation of a simple pendulum is given by T=2√lg where l is about 100 cm and known to have 1 mm accuracy. The period is about 2 s. The time of 100 oscillations is measured by a stopwatch of least count 0.1 s.
Detailed explanation-5: -A lift moving upwards with acceleration ‘a’, then, T = 2 × √(L/geff) = 2 √[L/(g + a)] If the lift is moving downward with acceleration ‘a’, then T = 2 × √(L/geff) = 2 √[L/(g – a)] More items