GENERAL KNOWLEDGE

GK

PHYSICS

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
Three resistors connected in parallel have individual values of 4.0, 6.0 and 10.0 ohm, respectively. If this combination is connected in series with a 12-V battery and a 2.0-ohm resistor, what is the current in the 10-ohm resistor?
A
0.59 A
B
1.0 A
C
11 A
D
16 A
Explanation: 

Detailed explanation-1: -REquivalent=4. 0+6. 0+10. 0=20.

Detailed explanation-2: -Thus, the expression for the three resistance connected in a parallel circuit is 1 R e q = 1 R 1 + 1 R 2 + 1 R 3 .

Detailed explanation-3: -⇒ 1/R(parallel) = 1/R2 + 1/R3. ⇒ R(parallel) = 4 . Now, the Resistor R1 = 4 is connected in series with the equivalent resistance of 12 and 6 in parallel. Hence to get the equivalent resistance of 8 we can connect 12 and 6 in parallel and then connect 4 in series.

Detailed explanation-4: -Given:-Three resistors of 5ohm, 10ohm &3ohm also these resistors are connected in parallel in the circuit and have the voltage of 6V. Let the required or the equivalent resistance be ‘R’. →R= 0.6333 (approx.) Hence, the equivalent resistance of the circuit will be 0.633 .

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