GK
PHYSICS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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What is the maximum height of a projectile launched with initial velocity f 25 m/s at an angle of 30
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7.98 m
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15.94 m
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31.89 m
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63. 76 m
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Explanation:
Detailed explanation-1: -Maximum height reached H=2gusin=20=5m.
Detailed explanation-2: -h = v 0 y 2 2 g . This equation defines the maximum height of a projectile above its launch position and it depends only on the vertical component of the initial velocity.
Detailed explanation-3: -Thus, the maximum height of the projectile formula is, H = u 2 sin 2 2 g .
Detailed explanation-4: -The maximum heighth of a projectile launched with initial vertical velocityv0y v 0 y is given by. h= v20y2g. The maximum horizontal distance traveled by a projectile is called the range.
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