GK
PHYSICS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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What is the velocity of a function in t f(t) = 2t²+7t-1 at t=5sec
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17m/s
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27m/s
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25m/s
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10m/s
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Explanation:
Detailed explanation-1: -The velocity function is the integral of the acceleration function plus a constant of integration. By Figure, v(t)=∫a(t)dt+C1=∫(5−10t)dt+C1=5t−5t2+C1.
Detailed explanation-2: -(b) The instantaneous velocity is v=dxdt=4.5t2, which, at time t=2.00s, yields v=(4.5)(2.00)2=18.0cm/s.
Detailed explanation-3: -Work out which of the displacement ( s ), initial velocity ( u ), acceleration ( a ), and time ( t ) you have to solve for final velocity ( v ). If you have u, a, and t, use: v = u + at. If you have s, u, and t, use: v = 2(s/t) − u . If you have s, a, and t, use: 13-Feb-2023
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