GK
PHYSICS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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What’s the period of a spring-mass oscillator with a mass of 3.5 kg and a spring constant of 85 N/m?
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1.3 sec
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1.9 sec
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0.4 sec
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0.8 sec
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3.1 sec
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Explanation:
Detailed explanation-1: -Mass on a spring-Where a mass m attached to a spring with spring constant k, will oscillate with a period (T). Described by: T = 2√(m/k).
Detailed explanation-2: -time is called T, the period of oscillation, so that T = 2, or T = 2/. The reciprocal of the period, or the frequency f, in oscillations per second, is given by f = 1/T = /2.
Detailed explanation-3: -Spring-Mass System Differential Equation A body of mass m is pulled by a force F, which is equal to mg. The displacement on the spring is x0. So, the force acting on it will be F =-kx0.
Detailed explanation-4: -The solution to the harmonic oscillator equation is(14.11)x=A cos(t+)where A is the amplitude and is the initial phase.
There is 1 question to complete.