GK
PHYSICS
Question
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When capacitors in parallel (3 capacitors), the equivalent capacitance is
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C = C1 + C2 + C3
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C = 1/C1 + 1/C2 + 1/C3
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C = QV1 + QV2 + QV3
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C = QV1 + QV2 + QV3
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Explanation:
Detailed explanation-1: -The equivalent capacitance of three capacitors of capacitance C1, C2 and C3 are connected in parallel is 12 units and product C1. C2. C3 = 48.
Detailed explanation-2: -The total capacitance for the two capacitors c1 and c2 when connected in parallel is derived by taking the sum of the capacitance of these two capacitors: Total capacitance = c1 +c2.
Detailed explanation-3: -Show that the effective capacitance, C, of a series combination, of three capacitors, C1, C2 and C3 is given by C = C1C2C3/(C1C2 + C2C3 + C3C1)
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