GK
PHYSICS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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C = C1 + C2 + C3
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1/C = 1/C1 + 1/C2 + 1/C3
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C = QV1 + QV2 + QV3
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C = CR1 + CR2 + CR3
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Detailed explanation-1: -Answer: Canceling the charge Q, we obtain an expression containing the equivalent capacitance, CS, of three capacitors connected in series: 1CS=1C1+1C2+1C3. This expression can be generalized to any number of capacitors in a series network.
Detailed explanation-2: -Let we have three capacitors C1, C2 and C3. In parallel combination, potential difference across each capacitor remains same i.e., V. Since each capacitor enjoys the same potential difference across it so it is in a position to store charge according to its capacity.
Detailed explanation-3: -Solution. Since C1andC2 C 1 and C 2 are in series, their equivalent capacitance CS C S is obtained with Equation 8.7: 1CS=1C1+1C2=11.000F+15.000F=1.200F⇒CS=0.833F.