MUSCLE PHYSIOLOGY

PHYSIOLOGY

MUSCLE ENERGETICS GLYCOLYSIS

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
The Krebs Cycle begins when Acetyl-CoA (2C) joins Oxaloacetic Acid (4C) to form ____
A
Citric Acid (6C)
B
Fumaric Acid (4C)
C
Malic Acid (4C)
D
a-Ketoglutaric Acid (5C)
Explanation: 

Detailed explanation-1: -Every pyruvate molecule produced by glycolysis enters the Krebs cycle as Acetyl CoA. Acetyl CoA combines with the 4C-oxaloacetate to form a 6C-compound that is citric acid. Citric acid is then oxidized breaking one of the C-C bonds to form carbon dioxide and reduce NAD to NADH.

Detailed explanation-2: -The Krebs cycle starts with condensation of acetyl group with oxaloacetic acid (OAA) and water to yield citric acid. This reaction is catalysed by the enzyme citrate synthase and a molecule of CoA is released.

Detailed explanation-3: -In the presence of oxygen, a molecule of CO2 and two hydrogen atoms are split from pyruvic acid, and acetyl-coenzyme A (acetyl-CoA) is formed. Acetyl-CoA combines with oxaloacetic acid in the Krebs cycle to form the six-carbon atom citric acid.

Detailed explanation-4: -Oxaloacetic acid is a 4C compound that takes part in the tricarboxylic acid cycle. The Kreb cycle was first discovered by Sir Hans Krebs in 1937. This cycle is also named a Citric acid cycle or Tricarboxylic acid cycle.

Detailed explanation-5: -Acetate joins with oxaloacetate. Acetate (2C) combines with oxaloacetate (4C), forming a 6C molecule called citrate.

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