STATISTICAL TECHNIQUES AND TOOLS
CHI SQUARE
Question
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The district manager of four different restaurants wanted to investigate whether the four restaurants differed with respect to customers ordering dessert or not based on family classification (with children or without children). Independent random samples of 100 customers who ordered dessert were selected from each restaurant, and the customers were identified as either being with children or without children. After verifying the conditions for the appropriate hypothesis test, the manager calculated a chi-square test statistic of 6.45 with an associatedp-value of 0.092. Based on the p-value and
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There is convincing statistical evidence to suggest that the proportion of customers who order dessert at each restaurant is the same based on family classification.
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There is convincing statistical evidence to suggest that the proportion of customers who order dessert at each restaurant is not the same based on family classification.
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There is not convincing statistical evidence to prove that the proportion of customers who order dessert at each restaurant is not the same based on family classification.
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There is not convincing statistical evidence to suggest that the proportion of customers who order dessert at each restaurant is the same based on family classification.
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There is not convincing statistical evidence to suggest that the proportion of customers who order dessert at each restaurant is not the same based on family classification.
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Explanation:
Detailed explanation-1: -How are the expected counts calculated when a chi-square goodness-of-fit test is conducted? The expected counts are calculated by multiplying each proportion in the null hypothesis by the sample size.
Detailed explanation-2: -Step 1: Organize all given data into a contingency table. Step 2: Append row and column totals to the contingency table. Step 3: Use the expected count formula to calculate the expected count of each cell in the contingency table. More items
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