STATISTICAL TECHNIQUES AND TOOLS
CONFIDENCE INTERVALS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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In a survey of 104 students, it was found that 79 went to the homecoming game this year.A 99% confidence interval for p is (0.652, 0.868). Interpret this interval.
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99% of the time the true proportion of people who went to the homecoming game this year is between 65.2% and 86.6%.
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The probability that the population proportion of people who went to the homecoming game this year is between 65.2% and 86.6% is 95%.
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Based on this sample, I am 99% confident that the true proportion of people who went to the homecoming game this year is between 65.2% and 86.6%.
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99% of all possible intervals calculated this way will capture the true proportion of people who went to the homecoming game this year
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Explanation:
Detailed explanation-1: -In a survey of 104 students, it was found that 79 went to the homecoming game this year. A 99% confidence interval for p is (0.652, 0.868). Interpret this interval. 99% of the time the true proportion of people who went to the homecoming game this year is between 65.2% and 86.6%.
Detailed explanation-2: -A larger sample size or lower variability will result in a tighter confidence interval with a smaller margin of error. A smaller sample size or a higher variability will result in a wider confidence interval with a larger margin of error.
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