ABDOMINAL
RENAL REPLACEMENT THERAPY
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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The cells exposed to the solution will burst.
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The cells exposed to the solution will shrink.
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The cells will remain the same size.
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The cells exposed to the solution will expand but not burst.
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Detailed explanation-1: -0.9% NaCl is isotonic to red blood cells. Which of these describes what will happen if a technician misplaces a decimal point and makes 9.0% NaCl solution instead and administers it to a patient? The cells exposed to the solution will shrink.
Detailed explanation-2: -When a red blood cell is placed in an isotonic solution, there will be no net movement of water. Both the concentration of solute and water are equal both intracellularly and extracellularly; therefore, there will be no net movement of water towards the solution or the cell.
Detailed explanation-3: -If a red blood cell (intracellular concentration of 0.9% salt) is placed into a test tube containing 10% salt solution, what would happen to it? It would fill with water and burst. No worries! We’ve got your back.
Detailed explanation-4: -The red blood cell has its normal volume in isotonic NaCl. Erythrocytes remain intact in NaCl 0.9%, resulting in an opaque suspension.
Detailed explanation-5: -The effects of hypertonic NaCl. The red blood cells, therefore, lose their normal biconcave shape and shrink or crenate.