AP BIOLOGY

BIOCHEMISTRY

POLAR AND NONPOLAR MOLECULES

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
Which two atoms in the periodic table form the most polar bond?
A
fluorine (F) and francium (Fr)
B
chlorine (Cl) and cesium (Cs)
C
fluorine (F) and cesium (Cs)
D
chlorine (Cl) and francium (Fr)
Explanation: 

Detailed explanation-1: -Thus the electronegativity difference between fluorine and iodine is highest due to which they form the most polar bond. Molecules of all halogens are diatomic. What this means is that their molecules exist with two atoms each.

Detailed explanation-2: -Hence, maximum electronegativity difference is seen in carbon and fluorine (C-F). Thus, the C-F bond has the most polar character.

Detailed explanation-3: -Given that fluorine is the most polar element, the pair of atoms with the most polar bond will be either the fluorine-phosphorus or fluorine-silicon pairs. Determining which is the most polar depends on the electronegativity of phosphorus and silicon.

Detailed explanation-4: -The above discussion suggests that the highest electronegative difference is in the HF molecule, which is 1.78. Therefore the bond between H-F is most polar.

Detailed explanation-5: -MQ:Which element will form the most polar bond with fluorine? Boron will form the most polar bond with fluorine. Electronegativity values increase from left to right across the periods of the periodic table and decrease down the column.

There is 1 question to complete.